A Carnot engine whose heat sinks at 27°C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?
Text Solution
Verified by ExpertsThe correct answer is:
B
T=400K
If efficiency increased by 100% then new
efficiency 
n' = 50%
T'=600K
Increase in temp = 600 - 400
= 200K or 200°C
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